These are year-day methods for the setter generics.
set_year()sets the Gregorian year.set_day()sets the day of the year. Valid values are in the range of[1, 366].There are sub-daily setters for setting more precise components.
Usage
# S3 method for class 'clock_year_day'
set_year(x, value, ...)
# S3 method for class 'clock_year_day'
set_day(x, value, ...)
# S3 method for class 'clock_year_day'
set_hour(x, value, ...)
# S3 method for class 'clock_year_day'
set_minute(x, value, ...)
# S3 method for class 'clock_year_day'
set_second(x, value, ...)
# S3 method for class 'clock_year_day'
set_millisecond(x, value, ...)
# S3 method for class 'clock_year_day'
set_microsecond(x, value, ...)
# S3 method for class 'clock_year_day'
set_nanosecond(x, value, ...)Arguments
- x
[clock_year_day]A year-day vector.
- value
[integer / "last"]The value to set the component to.
For
set_day(), this can also be"last"to set the day to the last day of the year.- ...
These dots are for future extensions and must be empty.
Examples
x <- year_day(2019)
# Set the day
set_day(x, 12:14)
#> <year_day<day>[3]>
#> [1] "2019-012" "2019-013" "2019-014"
# Set to the "last" day of the year
set_day(x, "last")
#> <year_day<day>[1]>
#> [1] "2019-365"
# Set to an invalid day of the year
invalid <- set_day(x, 366)
invalid
#> <year_day<day>[1]>
#> [1] "2019-366"
# Then resolve the invalid day by choosing the next valid day
invalid_resolve(invalid, invalid = "next")
#> <year_day<day>[1]>
#> [1] "2020-001"
# Cannot set a component two levels more precise than where you currently are
try(set_hour(x, 5))
#> Error in set_hour(x, 5) :
#> Can't perform this operation because of the precision of `x`.
#> ℹ The precision of `x` must be at least "day".
#> ℹ `x` has a precision of "year".